Question

Factorize 1 + 64a3
using suitable identity:

Answer 1

HERE IS YOUR ANSWER.....^_^....

FACTORIZE:-

1+64a^3

=(1)^3+(4a)^3

=(1+4)(1-4a+16a^2)

Hence, (1+4) (1-4a+16a^2).

Answer 2

Hey here is your answer
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$= 1 + 64 {a}^{3} \\ = {1}^{3} + {(4a)}^{3} \\ = (1 + 4a)( {(4a)}^{2} - (4a \times 1 ) + {(1)}^{2}) \\ = (1 + 4a)(16 {a}^{2} - 4a + 1)$
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