Factorize 1 + 64a3 using suitable identity
Anonymous:
Is it ( 1 + 64a^3 ) ?
Is it a to the power 3 ?
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(1+8a)^3
(a+b)^3= a^3 + b^3 +3ab(a+b)
=1^3 + (8a)^3 +3(1)(8a){1+8a}
=1 + 64a^3 + 24a( 1+8a)
=1 + 64a^3 +24a + 192a^2
(a+b)^3= a^3 + b^3 +3ab(a+b)
=1^3 + (8a)^3 +3(1)(8a){1+8a}
=1 + 64a^3 + 24a( 1+8a)
=1 + 64a^3 +24a + 192a^2
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