Question

factorize
1/64x^3-8y^3-3/8x^y+3xy^2​

Answer 1

Answer:

$( \frac{x}{4} - 2y)( \frac{x}{4} - 2y)( \frac{x}{4} - 2y)$

Step-by-step explanation:

$\frac{ {x}^{3} }{64} - 8 {y}^{3} - \frac{3 {x}^{2}y }{8} + 3x {y}^{2}$

${ (\frac{x}{4}) }^{3} - {(2y)}^{3} - 3 ({ \frac{x}{4} )}^{2} 2y \: + 3( \frac{x}{4} ) ({2y})^{2}$

using the identity

${a}^{3} - {b}^{3} - 3 {a}^{2}b + 3a {b }^{2} = {(a - b)}^{3}$

here a = x/4, b = 2y

Now

${( \frac{x}{4} - 2y)}^{3}$

$( \frac{x}{4} - 2y)( \frac{x}{4} - 2y)( \frac{x}{4} - 2y)$

Hope it helps u . pls mark this answer as brainliest