FACTORIZE
100-(x-5)²
Answers
Answered by
1
Answer:
(x+5) (x-15)
Step-by-step explanation:
100-(x-5)²
Using identity:(a-b)^2=a^2+b^2-2ab
100-[x^2+25-2×x×5]
100-(x^2+25-10x)
100-x^2-25+10x
75-x^2+10x
-(x^2-10x-75)=0
(x^2-10x-75)=0
x^2-15x+5x-75=0
x(x-15)+5(x-15) =0
(x+5)(x-15) =0
Hope it's help u!
prajwallakra05:
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Answered by
3
Answer:
factorise means resolve or be resolvable into factors.
the factorisation of 100 -(x-5) ² may be done in many way
the easiest way -
100 - (x-5)²
(10)²-(x-5)²
now using identity
a²-b² = (a+b)(a-b)
(10+x-5)(10-x+5)
(5 +x )( 15 - x )
so the answer is (5 +x) (15-x)
tips :
- please try to learn all the identies
- and maintain the flow of wirting
- do the calculate very carefully
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