factorize 12 y^3 -14y^2-10y
Answers
Answered by
1
Answer:
12 y^3 - 14y^2 - 10y = 0
=> 2y( 6y^2 - 7y - 5) = 0
=> 6y^2 - 10y + 3y - 5 = 0
=> 2y( 3y - 5) + 1( 3y - 5) = 0
=> (2y + 1) ( 3y - 5) = 0
Now, either (2y + 1) = 0 or (3y - 5) = 0
=> y = -1/2 or 5/3....
Similar questions