Question

factorize 125 a³+b³/27​

Answer 1

Answer:

Answer:

To factorise 125a³ + b³/27

By looking at the question, we come to the conclusion that both the terms are perfect cubes. Hence we how to find a identity which can incorporate it.

we can find answer through the following identity

identity :

\boxed{x^3 +y^3 = (x+y)(x^2 -xy+y^2)}x3+y3=(x+y)(x2−xy+y2)

substitute the values  in it

x³ = 125a³

y³= b³/27

⇒ x = 5a

⇒ y = b/3

x³+y³ =125a³+b³/27  thus , we get

⇒ 125a³+ b³/27 = (5a+b/3)(25a²-5ab/3 + b²/9)

\begin{gathered}\\also,\boxed{x^3 -y^3 = (x-y)(x^2 +xy+y^2)}\end{gathered}also,x3−y3=(x−y)(x2+xy+y2)

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