factorize: 125x^3+27y^3
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Answered by
14
125x^3 + 27y^3
=(5x)^3 + (3y)^3.
using a^3 + b^3 = (a+b)(a^2 + b^2 -ab).
(5x + 3y)(25x^2 + 9y^2 - 15xy).
=(5x)^3 + (3y)^3.
using a^3 + b^3 = (a+b)(a^2 + b^2 -ab).
(5x + 3y)(25x^2 + 9y^2 - 15xy).
Answered by
5
Answer : ( 5x + 3y ) ( 25x^2 - 15xy + 9y^2 )
Step-by-step explanation:
using the identity a^3 + b^3 = ( a+b ) ( a^2 - ab + b^2 )
(5x)^3 + (3y) ^3
(5x + 3y) ( (5x)^2 - 5x Ă— 3y + (3y) ^2 )
(5x + 3y) ( 25x^2 - 15xy + 9y^2 )
hence,
125x^3 + 27y^3 = ( 5x + 3y ) ( 25x^2 - 15xy + 9y^2 )
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