Math, asked by hemanthguttapalli, 1 month ago

Factorize 125ycube-27zcube​

Answers

Answered by shriraam02007
0

Answer:

( 5y - 3z) (25y^2 + 15yz + 9z^2)

Step-by-step explanation:

125y^3 - 27z^3

= (5y)^3 - (3z)^3

= (5y - 3z)(5^2y^2 + 5 * 3yz + 3^2 z^2 )

= ( 5y - 3z) (25y^2 + 15yz + 9z^2)

125y^3 - 27z^3 =  ( 5y - 3z) (25y^2 + 15yz + 9z^2)

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Answered by kritikamaan31
1

Answer:

(5y-3z) (25y^{2}+ 15yz + 9z^{2})

Step-by-step explanation:

125y^{3}  - 27z^{3}\\ (5y)^{3} - (3z)^{3} \\ (5y-3z)[(5y)^{2} + (5y)(3z) +(3z)^{2}] \\  (5y-3z)(25y^{2} + 15yz+9z^{2})

Using-Identity --> (a^{3} - b^{3} ) = (a-b)(a^{2}  +ab+b^{2})

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