Math, asked by mithunn30, 1 year ago

factorize 12y²+ 28y-5

Answers

Answered by vinayhukkeri
0

 = 12 {y}^{2}  + 28y - 5 \\  = 12 {y}^{2}  + 30y - 2y - 5 \\  = 6y(2y + 5) - 1(2y + 5) \\  = (2y + 5)(6y - 1)
Answered by Varun1870
2

12y²+28y-5

12y²+30y-2y-5

6y(2y+5)-1(2y+5)

(2y+5)(6y-1)

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