Question

factorize 14(3x-5y)³+7(3x-5y)²​

Answer 1

$Given \: 14(3x-5y)^{3} + 7(3x-5y)^{2}$

$= \pink{7} \times 2\blue{ (3x-5y)^{2}}(3x-5y) + \pink {7} \blue{(3x-5y)^{2}}$

/* Take 7(3x-5y)² common */

$= \pink {7} \blue{(3x-5y)^{2}}[ 2(3x-5y) + 1]$

$= \pink {7} \blue{(3x-5y)^{2}}( 6x - 10y + 1 )$

$= \pink {7} \blue{(3x-5y)(3x-5y)}( 6x - 10y + 1 )$

Therefore.,

$\red { Factors \: of \: 14(3x-5y)^{3} + 7(3x-5y)^{2}}$

$\green { = \pink {7} \blue{(3x-5y)(3x-5y)}( 6x - 10y + 1 )}$

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Answer 2

Answer:

(ii) 14(3x – 5y)3 + 7(3x – 5y)2

= 7(3x – 5y)2 [2(3x – 5y) +1]

= 7(3x – 5y)2 (6x – 10y + 1)

Step-by-step explanation:

I HOPE THIS HELPED:)