Question

Factorize : (15a2 + 120a)​

Answer 1

Answer:

15a(a+8)

Step-by-step explanation:

15a2+120a

=15a*3a+15a*8

=15a(3a+8)

Answer 2

Answer:

Required factors are 15,a and (a+8).

Step-by-step explanation:

Given, $15 {a}^{2} + 120a$

We want to factorise it.

First we are taking common a from both expression,

$a(15a + 120)$

Now taking common 15 from both expression,

$15a(a + 8)$

Therefore, required factors are 15,a and (a+8).

This is a problem of factor part of Algebra.

Some important Algebra's formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$

Two more important Algebra's problem:

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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