Question

factorize 15x2+224x-15​

Answer 1

$15x^2+224x-15=0\\15x^2+225x-x-15=0\\15x(x+15)-(x+15)=0\\(x+15)(15x-1)\\\boxed{x =-15}or\boxed{x=1/5}$

Answer 2

$\huge \purple { \mathfrak{answer}}$

Here , we use splitting the middle term method to factorise

$\implies \sf {15x}^{2} + 224x - 15$

• In Order to factorise intially we have to multiply the Coefficient of ` x ` and last term of the expression given .

[On Multiplying we get , 15 × 15 = 225]

• Later , list out the factors of the product and check wether either the sum or difference of the two factors is equal to the second term of the expression .
• Like , here we got 225 . It can be factorised as :

1. 225 × 1
2. 15 × 15

• Among them as mentioned 225 - 1 = 224 . So we choose it and split the middle term

$\implies \sf {15x}^{2} + 225x - 1x - 15$

• Later , take the common of two terms at start and the third and fourth next .

$\implies \sf 15x(x + 15) - 1(x + 15)$

• For the first factors simply take the ones inside the brackets .
• For the second ones take the rest terms left over .

Hence , the factors of the expression are 15x² + 224 - 15 are (x + 15) and ( 15x - 1 )

*The terms in the brackets will be the same for both the parts!!