Question

Factorize (16−1), list the identities used.

Answer 1

Step-by-step explanation:

(16-1)

[(4)²-(1)²]

we know, a²-b²=(a+b)(a-b)

so, (4-1)(4+1)

Answer 2

Given data,

$(16-1)$

Now we have to factorize the given question.

Here $16$ can be written as $4^{2}$

Also $1$ can be written as $1^{2}$

$(4^{2} -1^{2} )$

The above is in the form of $a^{2}- b^{2}$

Formula for $a^{2}- b^{2}=(a+b)(a-b)$

Here,

$a=4$

$b=1$

Substitute these values in the formula.

We get,

$(4+1)(4-1)$

Therefore, the final answer after factorization is $(4+1)(4-1)$