Factorize 16-17z+z^2.Please solve it fast.Tmrrw is my test
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Z^2 - 17z +16
Now, Factorising,
=> z² - 2× 4z × 2 + 2² - 2²+ ( 4 ) ²
=> ( z - 2 )² - 2² +4²
=> ( z - 2 )² - 4 +16
=> ( z - 2 )² - 12
By using identity,
[ a ² - b ² = ( a + b ) ( a - b )]
=> ( z- 2 )² - ( √12 )²
=> ( z - 2 - √12 ) ( z - 2 + √12 )
Now, Factorising,
=> z² - 2× 4z × 2 + 2² - 2²+ ( 4 ) ²
=> ( z - 2 )² - 2² +4²
=> ( z - 2 )² - 4 +16
=> ( z - 2 )² - 12
By using identity,
[ a ² - b ² = ( a + b ) ( a - b )]
=> ( z- 2 )² - ( √12 )²
=> ( z - 2 - √12 ) ( z - 2 + √12 )
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