Question

factorize 16(5x+4)^2 - 9(3x-2)^2​

Answer 1

Step-by-step explanation:

=16[(5x)^2+(4)^2+2(5x)(4)]-9[(3x)^2+(2)^2-2(3x)(2)]

=16(25x^2+16+140x)-9(9x^2+4-12x)

=400x^2+256+2240x-81x^2-36+108x

=319x^2+2348x+220

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Answer 2

Answer:

16(5x+4)²-9(3x-2)²

a^m x b^m = ab^m

(4)²(5x+4)2-(3)²(3x-2)²

[4(5x+4)]²-[3(3x-2)]²

using a²-b²=(a+b)(a-b)

[4(5x+4)-3(3x-2)][4(5x+4)+3

(3x-2)]