Factorize 16-x square -2xy -y square
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Answer:
16-x²- 2xy - y²
16- ( x²+ 2xy+ y²)
16 - (x+ y)²
( 4+x+ y)(4-x-y) ( using a²- b² = (a+ b)(a-b)
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Answer:
16 - x² - 2xy - y² = (4 + x + y)(4 - x - y)
Step-by-step explanation:
We have,
16 - x² - 2xy - y²
Taking negative common
= 16 - (x² + 2xy + y²)
We know that,
(x + y)² = x² + 2xy + y²
= 16 - (x + y)²
Let's say (x + y) = A
So,
= 16 - (A)²
= 4² - A²
Using the identity,
x² - y² = (x + y)(x - y)
So,
4² - A² = (4 + A)(4 - A)
Now,
we said, A = (x + y)
So,
4² - (x + y)² = (4 + (x + y))(4 - (x + y))
= (4 + x + y)(4 - x - y)
Thus,
16 - x² - 2xy - y² = (4 + x + y)(4 - x - y)
Hope it helped and believing you understood it........All the best
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