factorize 16a²+4b²+25c²-16ab+20bc+40ac
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Hi ,
I think it may be like this
16a² + 4b² + 25c² + 16ab + 20bc + 40ac
= (4a)²+(2b)²+(5c)²+2(4a)(2b)+2(2b)(5c)+2(5c)(4a)
= ( 4a + 2b + 5c )²
= ( 4a + 2b + 5c )( 4a + 2b + 5c )
I hope this helps you.
: )
I think it may be like this
16a² + 4b² + 25c² + 16ab + 20bc + 40ac
= (4a)²+(2b)²+(5c)²+2(4a)(2b)+2(2b)(5c)+2(5c)(4a)
= ( 4a + 2b + 5c )²
= ( 4a + 2b + 5c )( 4a + 2b + 5c )
I hope this helps you.
: )
7837:
but there is -16ab in the given question
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