factorize :
2 2 2
ab - bc -ab +c
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Q. ab²-bc²-ab+c²
So, First set up it as ab² - ab - bc² + c².
Then, ab( b - 1 ) - c² ( b - 1 )
= ( b - 1 ) ( ab - c² )
So, First set up it as ab² - ab - bc² + c².
Then, ab( b - 1 ) - c² ( b - 1 )
= ( b - 1 ) ( ab - c² )
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