Question

factorize :
     2        2             2
ab     - bc    -ab   +c

Answer 1

Q. ab²-bc²-ab+c²
So, First set up it as ab² - ab - bc² + c².
Then, ab( b - 1 ) - c² ( b - 1 )
= ( b - 1 ) ( ab - c² )

Answer 2

Your Answer is here
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$= {ab}^{2} - ab - {bc}^{2} + {c}^{2} \\ \\ = ab(b - 1) - {c}^{2} (b - 1) \\ \\ = (b - 1)(ab - {c}^{2} )$
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