factorize 2√2a3-3√3b3
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Answer:
(√2a - √3b) ( 2a² + 3b² + √6ab)
Step-by-step explanation:
2√2a³ - 3√3b³
= (√2a)³ - (√3b)³
= (√2a - √3b)³ + 3√6ab(√2a - √3b)
=(√2a - √3b) [ (√2a - √3b)² + 3√6ab]
=(√2a - √3b) ( 2a² + 3b² + √6ab)
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