Question

Factorize 2√2x^3+3 3y^3 with suitable identity

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

(√2x+√3y) (2x²+3y³-√6xy) is the factorisation of the above equation.

Step-by-step explanation:

The three algebraic identities in Maths are:

Identity 1: (a+b)2 = a2 + b2 + 2ab.

Identity 2: (a-b)2 = a2 + b2 – 2ab.

Identity 3: a2 – b2 = (a+b) (a-b)

But the identity we will use is

A³+B²= (A+B)(A²+B²-AB)

now ,

Here

A= √2x

B=√3y

Hence ,

√2x³ + √3y³ = (√2x + √3y) (√2x )²+ (√3y)²-(√2x)( √3y)

=(√2x+√3y) (2x²+3y³-√6xy).

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