Math, asked by manashisaha12333, 10 months ago

factorize: 2(m2+n2)-3mn(m2+n2)-2m2n2 please answer step by step

Answers

Answered by hearthacker54

Answer:

m3+n3+3mn(m+n). = (m+n)( m2−mn+n2)+3mn(m+n). = (m+n)(m2−mn+n2+ 3mn). = (m+n)(m2+2mn+n2). = (m+n)(m+n)2

Step-by-step explanation:

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Answered by Anonymous

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In all(m-n) is common.

(m-n)[(m^2+mn+n^2)-m(m+n)+n(m-n)^2]mn

(m-n)mn(m^2+mn+n^2-m^2-mn+nm^2–2mn^2+n^3)

(m-n)mn(n^2+nm^2–2mn^2+n^3)

(m-n)mn^2(n+m^2–2mn+n^2)

(m-n)mn^2[n+(m-n)^2]

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