Question

factorize
2(x+y)^2-9(x+y)-5

Answer 1

Step  1  :Equation at the end of step  1  : ((2x•((x+y)2))-9•(x+y))-5 Step  2  :Equation at the end of step  2  : (2x • (x + y)2 - 9 • (x + y)) - 5 Step  3  :Trying to factor by pulling out :

 3.1      Factoring:  2x3+4x2y+2xy2-9x-9y-5 

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -9x-9y 
Group 2:  2x3+4x2y 
Group 3:  2xy2-5 

Pull out from each group separately :

Group 1:   (x+y) • (-9)
Group 2:   (x+2y) • (2x2)
Group 3:   (2xy2-5) • (1)


Looking for common sub-expressions : 

Group 1:   (x+y) • (-9)
Group 3:   (2xy2-5) • (1)
Group 2:   (x+2y) • (2x2)

Final result :

2x3 + 4x2y + 2xy2 - 9x - 9y - 5

Answer 2

2(x + y)² - 9( x + y ) -5 = 0
⇒2(x + y)² - 10 (x+y) +1(x+y) -5 = 0
⇒2(x+y)(x + y - 5 ) + 1(x + y -5 ) = 0
taking (x + y -5 ) common , 
⇒(x + y -5 )[2(x + y) + 1]  =0 
⇒(x + y -5)(2x + 2y +1) =0

hence two factors are above 
hope , you got this 

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