factorize 2(x+y)³-6(x+y)
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=(x+y)[2(x+y)²-6]
=(x+y)(2)[(x+y)²-(√3)²]
=(x+y)(2)[(x+y)+√3][(x+y)+√3]
=(x+y)(2)[x+y+√3][x+y-√3]
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Step-by-step explanation:
(x+y)^3=x^3+y^3+3x^2y+3xy^2
=>2(x^3+y^3+3x^2y+3xy^2)-6(x+y)
=>2x^3+2Y^3+6x^2y+6xy^2-6x+6y
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