Question

Factorize:-

20x² - 27x + 8​

Answer 1

Correct Question:-

Factorize - 20x^2 -27x -8

To factorize:-

• 20x² - 27x - 8​

Solution:-

$\tt 20x^2 -27x - 8 \\\\ \tt Here, \\\\ \tt \star a=20 \\\\ \tt \star b =-27 \\\\ \tt \star c=-8 \\\\\\ \tt We \:\:have\:\:to\:\:find \:\:ac \:\: first \\\\ \tt So, ac= 20 \times 8=-160 \\\\ \tt \\\\Now\:\: factorize \:\: 160 \\\\ \tt 160 = 2 \times 2 \times 2 \times 2 \times 2 \times 5 \\\\ \tt Now\:\: we\:\: know\:\:that \:\:we\:\: have\:\: to\:\: find \:\: the \:\:summation \:\:of \:\: factors\\ of \:\:160\:that\:\: is \:\:27 \\\\ \tt 32-5=27 \\\\ \tt Now, \\\\ \tt 20x^2 -(32-5)x +8$

$\\\\ \tt =20x^2-32x +5x -8 \\\\ \tt =4x(5x-8) + 1(5x-8) \\\\ \tt =(4x+1)(5x-8)$

So, factors are (4x+1)(5x-8)