Question

factorize:-

24x^2-41x+12

Answer 1

=24x^2-9x-32x+12
=(24x^2-9x)-(32x-12)
=3x(8x-3)-4(8x-3)
=(8x-3) (3x-4)
This is the answer.

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Answer 2

${24}^{2} - 41x + 12 = 0 \\ {24}^{2} - 32x - 9x + 12 = 0\\ 8 |3x - 4| - 3 |3x - 4| = 0 \\ |8x - 4| |3x - 4| = 0 \\ thus \: \\ x = \frac{3}{4} andx = \frac{4}{3}$