factorize 25(2a-b)²-81b²
Answers
Answered by
158
Hi ,
we know the algebraic identity
x² - y² = ( x + y )(x - y )
Now ,
25(2a - b )² - 81b²
= [ 5 ( 2a - b )]² - ( 9b)²
= ( 10a - 5b )² - ( 9b )²
= ( 10a - 5b + 9b )(10a -5b - 9b )
= ( 10a + 4b ) ( 10a - 14b )
= [ 2 ( 5a + 2b ) ] [ 2( 5a - 7b )]
= 4(5a + 2b )(5a - 7b )
I hope this helps you.
:)
we know the algebraic identity
x² - y² = ( x + y )(x - y )
Now ,
25(2a - b )² - 81b²
= [ 5 ( 2a - b )]² - ( 9b)²
= ( 10a - 5b )² - ( 9b )²
= ( 10a - 5b + 9b )(10a -5b - 9b )
= ( 10a + 4b ) ( 10a - 14b )
= [ 2 ( 5a + 2b ) ] [ 2( 5a - 7b )]
= 4(5a + 2b )(5a - 7b )
I hope this helps you.
:)
satyaprakashjeoxts8r:
thanq so much brother
Answered by
45
Answer:
Step-by-step explanation:
25(2a-b)²-81b²
=[5(2a-b)]²-(9b)²
=(10a-5b)²-(9b)²
Using the formula a²-b²=(a+b)(a-b)
=(10a-5b+9b)(10a-5b-9b)
=(10a+4b)(10a-14b)
=[2(5a+2b)] [2(5a-7b)]
=4(5a+2b)(5a-7b)
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