Math, asked by satyaprakashjeoxts8r, 1 year ago

factorize 25(2a-b)²-81b²

Answers

Answered by mysticd
158
Hi ,

we know the algebraic identity

x² - y² = ( x + y )(x - y )

Now ,

25(2a - b )² - 81b²

= [ 5 ( 2a - b )]² - ( 9b)²

= ( 10a - 5b )² - ( 9b )²

= ( 10a - 5b + 9b )(10a -5b - 9b )

= ( 10a + 4b ) ( 10a - 14b )

= [ 2 ( 5a + 2b ) ] [ 2( 5a - 7b )]

= 4(5a + 2b )(5a - 7b )

I hope this helps you.

:)

satyaprakashjeoxts8r: thanq so much brother
Answered by Myself454
45

Answer:

Step-by-step explanation:

25(2a-b)²-81b²

=[5(2a-b)]²-(9b)²

=(10a-5b)²-(9b)²

Using the formula a²-b²=(a+b)(a-b)

=(10a-5b+9b)(10a-5b-9b)

=(10a+4b)(10a-14b)

=[2(5a+2b)] [2(5a-7b)]

=4(5a+2b)(5a-7b)

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