Question

factorize
25- 4a²- 12 ab- 96² 2​

Answer 1

Answer:

First of all, the correct question is: 4a²+12ab+9b² (There's a typo in your question)

Now, we can write it as (2a)² + 2(2a)(3b) + (3b)² which is of the form, x²+2xy+y² where x=2a and y=3b.

Also, x²+2xy+y² = (x+y)²

Therefore the given expression becomes, (2a+3b)². This is the required answer.

Answer 2

Answer:

$4a^{2} +12ab+9b^{2} =(2a+3b)^{2}$

Step-by-step explanation:

Given : $4a^{2} +12 ab +9b^{2}$

To find : Factors of the above equation

Solution :

• The given equation is  $4a^{2} +12ab+9b^{2}$
• We know the identity that

         $(a+b)^{2} =a^{2} +2ab+b^{2}$

• Now, we have to rearrange the given equation in the above equations format. We get

        $4a^{2}+12ab +9b^{2}=(2a)^{2} +2*2a*3b+(3b)^{2}$

                               = $(2a+3b)^{2}$

• ∴ $4a^{2} +12ab+9b^{2} =(2a+3b)^{2}$