Factorize 25(a + b)_161a - b)?
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Answer:
(i)25(a+b)2−16(a−b)2
=[5(a+b)]2−[4(a−b)]2
=(5a+5b)2−(4a−4b)2
=[(5a+5b)+(4a−4b)][(5a+5b)−(4a−ab)]
=(5a+5b+4a−4b)(5a+5b−4a+4b)
=(9a+b)(a+9b)
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hey mate ,hope this may help you
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