Math, asked by deimaphijana, 3 months ago

factorize 25 a²-4 b²+28 bc-49c²

Answers

Answered by purnapushkalam1991

0

Answer:

25 a²-4 b²+28 bc-49c²=25 a²-(4 b²-28 bc+49c²)

=(5a)²-((2b) ²-2*2*7 bc+(7c)²)

=(5a)²-(2b-7c)²=(5a+(2b-7c)) (5a-(2b-7c))

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