Question

Factorize (256x ^
16 – 1).
​

Answer 1

[(√2x)^16 -1]= [(16x^8)^2 -1]=

(16x^8 +1)(16x^8 -1)

(16x^8 +1){(4x⁴)² -1}

(16x^8. +1)(4x⁴+1)(4x⁴-1)

(16x⁴+1)(4x⁴+1)(2x²+1)(2x²-1).

or

(16x⁴+1)(4x⁴+1)(2x²+1)(√2.x+1)(√2.x-1)

i hope u will b understand. ..