Question

factorize 256x^4 - 81y^4

Answer 1

256x^4 - 81y^2 = 0
( 16x^2 + 9y^2) ( 16x^2 - 9y^2)= 0
(16x^2 + 9y^2) ( 4x + 3y ) ( 4x - 3y ) = 0

Answer 2

☆Hello friend☆

${256x}^{4} - {81y}^{4} \\ { {(16x}^{2}) }^{2} - { {(9y}^{2}) }^{2} \\ ( {16x}^{2} - {9y}^{2} )( {16y}^{2} + {9y}^{2} ) \\ (4x - 3y)(4x + 3y)({16y}^{2} + {9y}^{2} )$
Hope it helps

☺☺☺