Question

factorize 27 a cube b cube-45 a power4 b sqare​

Answer 1

$Given \:27a^{3}b^{3} - 45 a^{4}b^{2}$

$=( 9a^{3}b^{2}) \times 3 \times b - ( 9a^{3}b^{2}) \times 5a$

$= 9a^{3}b^{2} ( 3b - 5a )$

Therefore.,

$\red{Factors \:of \:27a^{3}b^{3} - 45 a^{4}b^{2}}$

$\green {= 9a^{3}b^{2} ( 3b - 5a )}$

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