Question

Factorize
27p^3 - 1/216 - 9/2p^2 + 1/4p

Answer 1

please refer to this
Hope this helps you.

Answer 2

Here I am putting p as x
${(3x)}^{3} - ( { \frac{1}{6}) }^{3} - 3({3x})^{2}( \frac{1}{6} ) - 3(3x) ({ \frac{1}{6}) }^{2} \\ {(3x - \frac{1}{6} )}^{3}$
Using identify (a b)^3 = a^3 - b^3 - 3a^2b - 3ab^2