Math, asked by madhugupta49075, 9 months ago

Factorize 27x4 - 8x

Answers

Answered by prisha0201
12

Answer; Which class' question is this?

x(27x³-8)

x[(3x)³-(2)³]

x[(3x-2){(3x)²+2²+6x}]

x(3x-2)(9x²+6x+4)

Answered by aleenaakhansl
1

Answer:

THE FACTORS ARE

(x) (3x-2) (9x²-6x+4)

Step-by-step explanation:

In mathematics, a divisor of an integer n, also called a factor of n, is an integer m that may be multiplied by some integer to produce n. In this case, one also says that n is a multiple of m.

X (27 x³-8)

X{ (3x)³ - 2³}

X {(3x-2)(3x²+2²+6x)}

X(3x-2)(9x²-6x+4)

Hence,

The factors are

  • X
  • 3x-2
  • 9x²-6x+4

(#SPJ3)

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