Factorize 27x4 - 8x
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12
Answer; Which class' question is this?
x(27x³-8)
x[(3x)³-(2)³]
x[(3x-2){(3x)²+2²+6x}]
x(3x-2)(9x²+6x+4)
Answered by
1
Answer:
THE FACTORS ARE
(x) (3x-2) (9x²-6x+4)
Step-by-step explanation:
In mathematics, a divisor of an integer n, also called a factor of n, is an integer m that may be multiplied by some integer to produce n. In this case, one also says that n is a multiple of m.
X (27 x³-8)
X{ (3x)³ - 2³}
X {(3x-2)(3x²+2²+6x)}
X(3x-2)(9x²-6x+4)
Hence,
The factors are
- X
- 3x-2
- 9x²-6x+4
(#SPJ3)
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