Question

Factorize 27y³+125z³

Answer 1

It is given that,

$27y^3+125z^3$

We have to factorize the given expression,

As we know that

$27$ is the cube of $3$ and $125$ is the cube of $5$

So, the expression becomes,

$(3y)^3+(5z)^3$

We know the identity for,

$(a^3+b^3)=(a+b)(a^2-ab+b^2)$

Therefore,

$=>(3y+5z)(9y^2-15yz+25z^2)$

Answer 2

As per data given in the question,

It is given in the question that,

We have to factorize the expression - $27 y^{3}+125 z^{3}$

As we know that

27 is the cube of 3 and 125 is the cube of 5

So, for solving the expression,

We can rewrite the given expression as,  

$(3 y)^{3}+(5 z)^{3}$  

As we know that,

$\left(a^{3}+b^{3}\right)=(a+b)\left(a^{2}-a b+b^{2}\right)$

So, applying the above identity for solving the expression,

We can rewrite the expression as,

the identity for,  

$=>(3 y+5 z)\left(9 y^{2}-15 y z+25 z^{2}\right)$