factorize:(2a+3b)^3-(2a-3b)^3
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Hey mate, Here's your answer:
(2a+3b)^3-(2a-3b)^3 is in the form of a^3-b^3
a^3-b^3=(a-b)(a^2+ab+b^2)
Thus,
(2a+3b-(2a-3b))((2a+3b)^2+2a+3b*2a-3b+(2a-3b)^2)
(2a+3b-2a+3b)(4a^2+12ab+9b^2+4a^2-9b^2+(4a^2-12ab+9b^2))
6b(4a^2+12ab+9b^2+4a^2-9b^2+4a^2-12ab+9b^2)
6b(12a^2+9b^2)
72a^2b+54b^3
hope it helps....
please mark it as Brainliest if it helps
(2a+3b)^3-(2a-3b)^3 is in the form of a^3-b^3
a^3-b^3=(a-b)(a^2+ab+b^2)
Thus,
(2a+3b-(2a-3b))((2a+3b)^2+2a+3b*2a-3b+(2a-3b)^2)
(2a+3b-2a+3b)(4a^2+12ab+9b^2+4a^2-9b^2+(4a^2-12ab+9b^2))
6b(4a^2+12ab+9b^2+4a^2-9b^2+4a^2-12ab+9b^2)
6b(12a^2+9b^2)
72a^2b+54b^3
hope it helps....
please mark it as Brainliest if it helps
Answered by
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Hope this helps......... Do mark my answer as brainliest...!
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@Reema
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