Math, asked by shreyarai8, 2 months ago

factorize
(2a-3b)³+(3b-4c)³+(4c-2a)³​

Answers

Answered by sid021
0

=> (2a-3b)³+(3b-4c)³+(4c-2a)³

=>(8a³-3×4a²×3b+3×2a×9b²-27b³)+(27b³-3×9b²×4c + 3×3b×16c²-64c³) + (64c³-3×16c²×2a +3×4c×4a² -8a³)

=>(8a³-36a²b+54ab²-27b³) + (27b³-108b²c+144bc² -64c³) + (64c³-96c²a+48ca²-8a³)

=> -36a²b+54ab²-108b²c+144bc²-96c²a+48ca²

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