Question

Factorize( 2a-3b+c)²
Thx​

Answer 1

Answer:

$</p><p>(2a-3b+c)^2\\ \\ \\</p><p>Identity\\ \\ \\</p><p> (a+b+c)^2= a^2+b^2+c^2+2(ab+bc+ca)\\ \\ \\</p><p>by \: using\: identity- \\ \\ \\</p><p>(2a)^2+(-3b)^2 + (c)^2 +2{(2a× -3b)+ (-3b×c)+(2a×c)}\\ \\ \\</p><p>= 4a^2+9b^2+c^2+2(-6ab-3bc+2ac)\\ \\ \\</p><p>= 4a^2+9b^2+c^2 -12ab-6bc+4ac$.

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Answer 2

I am used polynomial formula.