Question

Factorize:
2a²+2√6ab+3b²

Answer 1

Answer:

Please see the attachment

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Answer 2

The expression is given as : 2a² + 2√6ab + 3b²

By using an identity, a² - 2ab + b² = (a + b)² :  

Here the first and the third terms are perfect squares. The middle term = 2( product of square roots of the first and third terms) :  

= (√2a)² + 2 × √2a × √3b   + (√3b)²

 = (√2a + √3b)²

Hence,  the factorisation of 2a² + 2√6ab + 3b² is (√2a + √3b)².

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