Question

factorize 2a²+5ab+6ab+15b²​

Answer 1

Take product of first n last terms 2a^2×2b^2=4(ab)^2

Middle term is 5ab

We should find two terms such that their product 4(ab)^2 n their sum should be 5ab

That is 4ab and 1ab

Now you can write 2a²+4ab+ab+2b²=0

In simplification u will get (2a+b) (a+2b)=0

Answer 2

$\huge\underline \color{cyan}ANSWER$

$2a²+5ab+6ab+15b² \\We\<u> </u>arrange\ it\ to\ factorise, \\=2a²+6ab+5ab+15b²\\ = 2a(a + 3b) + 5b(a + 3b) \\ = (a + 3b)(2a + 5b)$