Question

factorize (2n-3)^2 - 8n+12



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Answer 1

Answer:

Step-by-step explanation:

(2n-3)^2-8n+12

(2n)^2-2.2n.3+3^2-8n+12

or, 4n^2-12n+9-8n+12

or, 4n^2-12n-8n+9+12

or, 4n^2-20n+21

or, 4n^2-(21-1)n+21

or, 4n^2- 21n+1n+21

or, n(4n-21)+n(1+21)

or, n{(4n-21)+(1+21)}

we cannot do anything further