Question

factorize (2x +1 )^2 - 9 (2x + 1) +20

Answer 1

let (2x+1) = a

so.....

a^2-9a+20

by splitting the mid tearm

a^2-4a-5a+20

a(a-4)-5(a-4)

(a-4)(a-5)

now put the value of a

(2x+1-4)(2x+1-5)

(2x+3)(2x+4)

Answer 2

Step-by-step explanation:

(2x+1)^2-9(2x+1)+20

4x+2-18x-9+20=0

18x+4x-2-9+20=0

22x-11+20=0

22x-11=0+20

22x-11=20

22x=20+11

22x=33

x=33/22

x=3/2

hope it helps you buddy...mark me as brainleist