Math, asked by qwertyuiop89, 1 year ago

factorize:√2x^2+9x+4√2

Answers

Answered by Chhavibansal
2

 \sqrt{2}  {x}^{2}  + 9x +  \sqrt[4]{2}
 \sqrt{2}  {x}^{2}  + 8x + x +   \sqrt[4]{2}
 \sqrt{2} x(x  +  \sqrt[4]{2} ) + 1(x +  \sqrt[4]{2} )
( \sqrt{2} x + 1)(x +  \sqrt[4]{2} )
Hope it will help you....
IF SO THAN MARK IT AS BRAINLYT...

Answered by Ankit02
11

Your Answer :-

The Question is from the Topic Quadratic Equations .

 \boxed{\sqrt{2} x^{2}  +9x +4\sqrt{2}=0 }

Multiplying by root 2

 \boxed{2x^{2} + 9\sqrt{2} x+ 8 = 0}

  \boxed{2x^{2} + 8\sqrt{2}x +\sqrt{2}x+ 8 = 0}

 \boxed {2 x( x +  4\sqrt{2} ) + \sqrt{2} ( x +  4\sqrt{2}) = 0}

 \boxed {(2x + \sqrt{2}  )  ( x + 4\sqrt{2})  = 0}

 \boxed{x = \frac{-\sqrt{2}}{2} }

 \boxed{ x = -4\sqrt{2} }

^_^ ^_^

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