Question

factorize:(2x-3)^2+(2x-3)-20​

Answer 1

Answer:

2x3 =6 x+2 (2x-3) -20

7x -19

Answer 2

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${(2x - 3)}^{2} + (2x - 3) - 20 \\ \\ \\ {inset \: the \: formula \: of \: {(a - b)}^{2} } \\ i.e \: {(a)}^{2} - 2ab + {(b)}^{2} = {(a - b)}^{2}$

$= {(2x)}^{2} - 2(2x)(3) + {(3)}^{2} + \: (2x - 3) - 20$

$= 4 {x}^{2} - 12x + 9 +( 2x - 3) - 20$

$remove \: the \: brackets \: and \: convert \: the \: symbols \: accordingly$

$= 4 {x}^{2} - 12x + 9 + 2x - 3 + 20$

$= 4 {x}^{2} - 12x + 2x + 9 - 3 + 20$

$= 4 {x}^{2} - 10x + 26$

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