factorize: 2x^3-x^2-13x-6
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f(x) = 2x3 + x2 − 13x + 6 Factors of constant term 6 are ±1, ± 2, ± 3, ± 6. Putting x = 2, we have: f(2) = 2(2)3 + 22 − 13 (2) + 6 = 16 + 4 − 26 + 6 = 0 Hence (x − 2) is a factor of f(x). Read more on Sarthaks.com - https://www.sarthaks.com/150058/use-the-remainder-theorem-to-factorise-the-following-expression-2x-3-x-2-13x-6?show=150066#a150066
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