Question

Factorize 2x + 4y - 8xy - 1 by regrouping method ​

Answer 1

Answer:

ANSWER

Given : 2x+4y−8xy−1

We can further write it as

2x+4y−8xy−1=2x−1−8xy+4y

By taking common terms out

2x+4y−8xy−1=(2x−1)−4y(2x−1)

So we get,

2x+4y−8xy−1=(2x−1)(1−4y)

Answer 2

Answer:

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