Question

factorize 2x^5 - 2x

help​

Answer 1

$2 {x}^{5} - 2x \\ = 2x( {x}^{4} - 1) \\ = 2x{( {x}^{2} + 1)( {x}^{2} - 1)} \\ = 2x( {x}^{2} + 1)(x + 1)(x - 1) \\ \\ { \huge{ \mathcal{ \ \: HOPE \: \: THIS \: \: HELPS \: \: U........}}}$

Answer 2

Answer:

$2x {}^{5} - 2x \\ = 2x(x {}^{4} - 1)$

Now,

We know

$(a {}^{2} - b {}^{2}) = (a + b)(a - b)$

So here in

$(x {}^{4} - 1)$

$a = x {}^{2} \\ b = 1$

So,

$(x {}^{4} - 1) \\ = (x {}^{2} + 1)(x {}^{2} - 1)$

Again in

$(x {}^{2} - 1)$

a = x and b = 1

$(x {}^{2} - 1) \\ = (x + 1)(x - 1)$

So

$2x {}^{5} - 2x \\ = 2x(x {}^{4} - 1) \\ = 2x(x {}^{2} + 1)(x {}^{2} - 1) \\ = 2x(x {}^{2} + 1)(x + 1)(x - 1)$

I hope, it will help you.