Question

Factorize:(-2x+5y-3z)2

Answer 1

hey dear here's ur answer
by applying (x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2zx
we get
(-2x+5y-3z)^2
= (-2x)^2+(5y)^2(-3z)^2+ 2×(-2x) ×5y +2 ×5y× (-3z)+2× (-3z) ×(-2x)
=4x^2 +25y^2 +9z^2 -20xy -30yz + 12zx
hope it helps..
with regards..
@anisha28

Answer 2

$\huge\sf\blue{{(-2x+5y-3z)}^{2}}$

$\huge{\underline{\tt{\green{Simplification-}}}}$

Given : a = -2x

b = 5y

$<strong>c </strong>= -3z$

${\underline{\tt{\orange{{Main\:Identity: (a+b+c)}^{2}={a}^{2}+{b}^{2}+{c}^{2}+2ab+2bc+2ca}}}}$

$\longrightarrow \sf{{(a-b-c)}^{2}={a}^{2}+{b}^{2}+{c}^{2}+2ab-2bc-2ca}$

$\longrightarrow \sf{{(-2x+5y-3z)}^{2}={-2x}^{2}+{3z}^{2}+{3z}^{2}+2\times2x\times5y-2\times5y\times3z-2\times3z\times2x}$

$\longrightarrow \sf\orange{{4x}^{2}+{25y}^{2}+{9z}^{2}+20xy-30yz-12zx}$