Question

factorize 2x(m-n)+4y(4m-4n)-6z(n-m)

Answer 1

$2x(m - n) + 4y(4m - 4n) - 6z(n - m) \\ = 2x(m - n) + 4y \times 4(m - n) + 6z(m - n) \\ = 2x(m - n) + 16y(m - n) + 6z(m - n) \\ = (m - n)(2x + 16y + 6z)$

Answer 2

Hey dood, here is ur answer

= 2x ( m - n ) + 4y ( 4m - 4n ) - 6z ( n - m )

Opening the brackets

= 2mx - 2nx + 16my - 16ny + 6mz - 6nz

= 2x ( m - n ) + 16y ( m - n ) - 6z ( m - n )

= { 2x + 16y - 6z } ( m - n )

Hope it helps