Factorize [2x-y-z]²
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Answer:
(2x-y-z)².
By using formula (a-b-c)²=a²+b²+c²-2ab+2bc-2ca where a=2x, b=y & c=z.
(2x-y-z)²=(2x)²+(y)²+(z)²-2(2x)(y)+2(y)(z)-2(z)(2x).
=4x²+y²+z²-4xy+2yz-4zx.
I think this is your answer.
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